Комбинаторика: Нахождение количества различных сумм при выборе карт из двух наборов

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Task 1

The problem asks us to find the number of different possible sums when picking one card from each set.

Set 1: Contains cards with numbers 3, 4, and 5.
Set 2: Contains cards with numbers 4 and 5.

To find all possible sums, we need to add each number from Set 1 to each number from Set 2.

  1. Pick 3 from Set 1:

    • 3 + 4 = 7
    • 3 + 5 = 8
  2. Pick 4 from Set 1:

    • 4 + 4 = 8
    • 4 + 5 = 9
  3. Pick 5 from Set 1:

    • 5 + 4 = 9
    • 5 + 5 = 10

Now, let's list all the sums we found: 7, 8, 8, 9, 9, 10.

To find the number of different sums, we remove any duplicates: 7, 8, 9, 10.

There are 4 different possible sums.

Answer: There are 4 different sums possible.

Варианты продолжения:
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Task 1

The problem asks us to determine the number of unique sums possible when selecting one card from each of two given sets.

Set 1: Contains cards with the numbers {3, 4, 5}.
Set 2: Contains cards with the numbers {4, 5}.

To find all possible sums, we systematically pair each number from Set 1 with each number from Set 2 and calculate their sum.

  1. If we pick '3' from Set 1:

    • Add '4' from Set 2: \(3 + 4 = 7\)
    • Add '5' from Set 2: \(3 + 5 = 8\)
  2. If we pick '4' from Set 1:

    • Add '4' from Set 2: \(4 + 4 = 8\)
    • Add '5' from Set 2: \(4 + 5 = 9\)
  3. If we pick '5' from Set 1:

    • Add '4' from Set 2: \(5 + 4 = 9\)
    • Add '5' from Set 2: \(5 + 5 = 10\)

The sums obtained are: 7, 8, 8, 9, 9, 10.

To find the number of different sums, we list the unique values from this set: {7, 8, 9, 10}.

Counting these unique sums, we find there are 4 different possible sums.

Answer: There are 4 different possible sums.

Варианты продолжения:
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